Posted by JP on Tuesday, October 21, 2008 at 12:03am.
The rotor is an amusement park ride where people stand against the inside of a cylinder. Once the cylinder is spinning fast enough, the floor drops out.
AWhat force keeps the people from falling out the bottowm of the ride?
I think that it's the Normal force?
BIf the coefficient of friction is 0.40 and the cylinder has a radius of 2.5m, what is the minimum angular speed the of the cylinder so the people don't fall out?
Do I use NL #2 Sum F=mv2/r
which=ma(sub)c ??
Also, how do I set up the math to solve for the angular speed?
Thank you

College Physics  Damon, Tuesday, October 21, 2008 at 7:05am
Yes, normal force = m v^2/r
max friction force up = mu m v^2/r
weight down = mg
slip when m g = m v^2/r
v^2 = r g

typo, left mu out  Damon, Tuesday, October 21, 2008 at 7:07am
Yes, normal force = m v^2/r
max friction force up = mu m v^2/r
weight down = mg
slip when m g = mu m v^2/r
v^2 = r g / mu
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