Posted by **JP** on Tuesday, October 21, 2008 at 12:03am.

The rotor is an amusement park ride where people stand against the inside of a cylinder. Once the cylinder is spinning fast enough, the floor drops out.

A-What force keeps the people from falling out the bottowm of the ride?

I think that it's the Normal force?

B-If the coefficient of friction is 0.40 and the cylinder has a radius of 2.5m, what is the minimum angular speed the of the cylinder so the people don't fall out?

Do I use NL #2 Sum F=mv2/r

which=ma(sub)c ??

Also, how do I set up the math to solve for the angular speed?

Thank you

- College Physics -
**Damon**, Tuesday, October 21, 2008 at 7:05am
Yes, normal force = m v^2/r

max friction force up = mu m v^2/r

weight down = mg

slip when m g = m v^2/r

v^2 = r g

- typo, left mu out -
**Damon**, Tuesday, October 21, 2008 at 7:07am
Yes, normal force = m v^2/r

max friction force up = mu m v^2/r

weight down = mg

slip when m g = mu m v^2/r

v^2 = r g / mu

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