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March 27, 2017

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The rotor is an amusement park ride where people stand against the inside of a cylinder. Once the cylinder is spinning fast enough, the floor drops out.


A-What force keeps the people from falling out the bottowm of the ride?
I think that it's the Normal force?

B-If the coefficient of friction is 0.40 and the cylinder has a radius of 2.5m, what is the minimum angular speed the of the cylinder so the people don't fall out?

Do I use NL #2 Sum F=mv2/r
which=ma(sub)c ??

Also, how do I set up the math to solve for the angular speed?
Thank you

  • College Physics - ,

    Yes, normal force = m v^2/r
    max friction force up = mu m v^2/r
    weight down = mg
    slip when m g = m v^2/r
    v^2 = r g

  • typo, left mu out - ,

    Yes, normal force = m v^2/r
    max friction force up = mu m v^2/r
    weight down = mg
    slip when m g = mu m v^2/r
    v^2 = r g / mu

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