Posted by **michael** on Monday, October 20, 2008 at 7:52pm.

a ball is thrown horizontally -> from the roof of a building 45.0 meters tall and lands 24.0 meters from the base. what was the balls initial speed?

OTHER QUESTION

a shotputter throws the shot with an initial speed of 15.5 m/s @ 34 degrees. calculate the horizontal distance thraveled by the shot if it leaves the hand at a height of 2.20 meters above the ground.

- physics -
**Damon**, Monday, October 20, 2008 at 8:29pm
like this one:

http://www.jiskha.com/display.cgi?id=1224543292

- physics -
**Damon**, Monday, October 20, 2008 at 8:38pm
shot putter

initial vertical velocity Vo = 15.5 sin 34 = 8.67

initial and always horizontal velocity U = 15.5 cos 34 = 12.9

initial z = 2.2

final z = 0

acceleration = -9.8

so

0 = 2.2 + 8.67 t -4.9 t^2

t = 2 seconds

in 2 seconds it goes 12.9*2 = 25.8

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