Posted by kelsey on Monday, October 20, 2008 at 4:32am.
Set the potential energy decrease M g H equal to the total kinetic energy. Then divide that up between translational and rotational parts. One is
(1/2) M V^2, and the other is (1/2)(1/2)M R^2(V^2/R^2) = (1/4) M V^2, so the translational part is 2/3 of the total, etc.
okay so i have mgh =15.1 and i set it equal to KErot + KE trans?
15.1= 1/2[(2/5 X 2 X .08^2) X (1/2 X 2 X v)^2]
that right?
You have an X where you need a + between the translational and rotational terms. Both terms should include V. Then you could solve for V. But they don't ask for V.
AOnce yopu have MgH, all you have to do is compute KE(tr) = (2/3) M g H and (KE)rot) = (1/3) M g H
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