Posted by Danreb on .
A girl shoots an arrow from the top of a cliff. The arrow is initially at a point 20 meters above the level field below. The arrow is shot at an angle of 30 degrees above the horizontal with a speed of 39.2m/s. How far out from the base of the cliff will the arrow land?
You need to first find the time in the air, from the vertical flight equation. You can figure the initial vertical velocity from the angle.
hcliff=vi*time -1/2 g time^2
solve for time.
Then, use that time for the horizontal equation..
i tried that. it doesnt work
nvm it works. thanksssssss