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A girl shoots an arrow from the top of a cliff. The arrow is initially at a point 20 meters above the level field below. The arrow is shot at an angle of 30 degrees above the horizontal with a speed of 39.2m/s. How far out from the base of the cliff will the arrow land?

  • physics! - ,

    You need to first find the time in the air, from the vertical flight equation. You can figure the initial vertical velocity from the angle.

    hcliff=vi*time -1/2 g time^2
    solve for time.

    Then, use that time for the horizontal equation..


  • physics! - ,

    i tried that. it doesnt work

  • physics! - ,

    nvm it works. thanksssssss

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