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September 2, 2014

September 2, 2014

Posted by **tony** on Sunday, October 19, 2008 at 1:00pm.

i just wanted to know if my answer of 74000 j was correct.

- physics -
**drwls**, Sunday, October 19, 2008 at 1:09pmThe radiative heat loss RATE of his body is

(Area)*(infrared emissivity)*(sigma)*(T2^4 - T1^4)

where T2 = 309 K and T1 = 293 K

(Temperature must be in K to use this formula).

sigma is the Stefan-Boltzmann constant, which you should have learned about.

There will also be a convective heat loss, but that is harder to calculate. It could be comparable to the radiative loss.

You will have to multiply the heat loss rate by 13.5 min*60 s/min to get the energy loss in that time.

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