Posted by Lucy on Sunday, October 19, 2008 at 10:52am.
a triangular shelf is to be placed in a curio cabinet whose sides meet at an angle of 105 degrees. If the edges of the shelf along the sides measures 56 centimeters and 65 centimeters, how long is the outside edge of the shelf? Round to the nearest tenth.
Thanks for any helpI stink at word problems!

Precalculus  Reiny, Sunday, October 19, 2008 at 10:58am
Suppose you laid the triangle down in front of you.
What would you see?
Would it not be a simple triangle with sides 56 and 65, and the angle contained between those two sides of 105º ?
clearly a Cosine Law question.
x^2 = 56^2 + 65^2  2(56)(65)cos 105º
solve for x
let me know what you got. 
Precalculus  Lucy, Sunday, October 19, 2008 at 11:06am
x=95.5 cm

Precalculus  Reiny, Sunday, October 19, 2008 at 11:12am
no, I got 96.15
x^2 = 56^2 + 65^2  2(56)(65)cos 105º
= 3136 + 4225  7280(.258819)
notice the last term will become positive, I think you subtracted it instead. 
Precalculus  Lucy, Sunday, October 19, 2008 at 11:21am
x^2=3136+4225(0.2588)
x^2=3136+4225+0.2588
x^2=7361.26
x=85.8 
Precalculus  Reiny, Sunday, October 19, 2008 at 11:24am
No ! your forgot an entire factor.
yours: x^2=3136+4225+0.2588
mine: x^2 = = 3136 + 4225  7280(.258819) 
Precalculus  Lucy, Sunday, October 19, 2008 at 11:46am
Try again
x^2=3136+42257280(0.2588)
x^2=9245.06
x=96.2 cm