for the graph of y=-5sin x/2, state frequency
for y = a sin kx
the period is 2pi/k
so isn't your equation y = -5sin(1/2)x ?
for k = 1/2
can you take it from there?
= 1/4?
no, the frequency is 1/2, namely the k value of
y = a sin kx.
for yours, the "period" is 2pi/(1/2) = 4pi
which means it takes 4pi radians on your graph to complete one complete sine curve.
by frequency we want the number of cycles of the sine or cosine curve we would get from 0 to 2pi, which would be 1/2 or the k value of the sin kx .
To determine the frequency of the graph of the function y = -5sin(x/2), we need to understand the relationship between the sine function and its frequency.
The general equation of a sine function is y = A*sin(Bx + C) + D, where A represents the amplitude, B represents the frequency (or number of cycles), C represents the phase shift, and D represents the vertical shift.
In our given function y = -5sin(x/2), the coefficient of x is (1/2), which is equivalent to B. Therefore, the frequency of the graph is given by the reciprocal of B, which is 2.
So, the frequency of the graph y = -5sin(x/2) is 2.