Saturday

August 23, 2014

August 23, 2014

Posted by **jerson** on Thursday, October 16, 2008 at 8:45pm.

- trig -
**Reiny**, Thursday, October 16, 2008 at 9:03pmfor y = a sin kx

the period is 2pi/k

so isn't your equation y = -5sin(1/2)x ?

for k = 1/2

can you take it from there?

- trig -
**jerson**, Thursday, October 16, 2008 at 9:04pm= 1/4?

- trig -
**Reiny**, Thursday, October 16, 2008 at 9:15pmno, the frequency is 1/2, namely the k value of

y = a sin kx.

for yours, the "period" is 2pi/(1/2) = 4pi

which means it takes 4pi radians on your graph to complete one complete sine curve.

by frequency we want the number of cycles of the sine or cosine curve we would get from 0 to 2pi, which would be 1/2 or the k value of the sin kx .

**Related Questions**

math/trig - What graph is traced by the equation (x, y) = (5sin 12t , 6−5 ...

trig - 5sin(2x)+4cos(x)=0

trig - 5sin(2x)+4cos(x)+0

cacl - cos(t)/(5sin(t)+8)^2 the answer i got was: xcos(t)/(5sin(t)+8)^2 this is ...

calculus - antiderivative f''=3x+5sin(x) f(0)=4 f'(0)=4 Find f(x) I got (1/2)x^3...

precalc - how to graph y=5sin[3[2-pi/6]]+2

trig - 5sin^2 270degrees -3cos180degrees-tan(-180degrees) i got -2 but I'm not ...

math - how would you solve for x: (3)^.5sin(2x)-2cos(2x)+2sin^2(x)=1 using trig ...

Math Trig - Find all solutions on the interval [0,2pi] for the following: 2sin^2...

math - the question asks to integrate cos(t)/(5sin(t)+8)^2 the answer i got was ...