Posted by jerson on Thursday, October 16, 2008 at 8:45pm.
for the graph of y=5sin x/2, state frequency

trig  Reiny, Thursday, October 16, 2008 at 9:03pm
for y = a sin kx
the period is 2pi/k
so isn't your equation y = 5sin(1/2)x ?
for k = 1/2
can you take it from there?

trig  jerson, Thursday, October 16, 2008 at 9:04pm
= 1/4?

trig  Reiny, Thursday, October 16, 2008 at 9:15pm
no, the frequency is 1/2, namely the k value of
y = a sin kx.
for yours, the "period" is 2pi/(1/2) = 4pi
which means it takes 4pi radians on your graph to complete one complete sine curve.
by frequency we want the number of cycles of the sine or cosine curve we would get from 0 to 2pi, which would be 1/2 or the k value of the sin kx .
Answer This Question
Related Questions
 math/trig  What graph is traced by the equation (x, y) = (5sin 12t , 6−5 ...
 trig  5sin(2x)+4cos(x)=0
 trig  5sin(2x)+4cos(x)+0
 cacl  cos(t)/(5sin(t)+8)^2 the answer i got was: xcos(t)/(5sin(t)+8)^2 this is ...
 calculus  antiderivative f''=3x+5sin(x) f(0)=4 f'(0)=4 Find f(x) I got (1/2)x^3...
 precalc  how to graph y=5sin[3[2pi/6]]+2
 trig  5sin^2 270degrees 3cos180degreestan(180degrees) i got 2 but I'm not ...
 math  how would you solve for x: (3)^.5sin(2x)2cos(2x)+2sin^2(x)=1 using trig ...
 Bar graph?  I need to create a bar graph for a retail store I created that ...
 Calculus  Find the length of the entire perimeter of the region inside r=5sin(...
More Related Questions