Posted by jerson on Thursday, October 16, 2008 at 8:45pm.
for y = a sin kx
the period is 2pi/k
so isn't your equation y = -5sin(1/2)x ?
for k = 1/2
can you take it from there?
= 1/4?
no, the frequency is 1/2, namely the k value of
y = a sin kx.
for yours, the "period" is 2pi/(1/2) = 4pi
which means it takes 4pi radians on your graph to complete one complete sine curve.
by frequency we want the number of cycles of the sine or cosine curve we would get from 0 to 2pi, which would be 1/2 or the k value of the sin kx .
Related Questions
math/trig - What graph is traced by the equation (x, y) = (5sin 12t , 6&#...
trig - 5sin(2x)+4cos(x)=0
trig - 5sin(2x)+4cos(x)+0
calculus - antiderivative f''=3x+5sin(x) f(0)=4 f'(0)=4 Find f(x) I ...
cacl - cos(t)/(5sin(t)+8)^2 the answer i got was: xcos(t)/(5sin(t)+8)^2 this is ...
precalc - how to graph y=5sin[3[2-pi/6]]+2
trig - 5sin^2 270degrees -3cos180degrees-tan(-180degrees) i got -2 but I'm ...
math - the question asks to integrate cos(t)/(5sin(t)+8)^2 the answer i got was ...
Math Trig - Find all solutions on the interval [0,2pi] for the following: 2sin^2...
math - the question asks to integrate cos(t)/ (5sin(t)+8)^2 the answer i got was...
For Further Reading
