Tuesday

July 22, 2014

July 22, 2014

Posted by **George** on Thursday, October 16, 2008 at 6:21pm.

For the global maximum at x=none, But for the Global minimum at x=?

Is the Global minimum 0 or nonw? Any help would be greatly appreciated.

- Calculus -
**Reiny**, Thursday, October 16, 2008 at 7:15pmI always encouraged my students to make a rough sketch of the graph.

Pick any 5 or 6 positive x's, then find their y values.

Pick an x close to zero (e.g. x = .00001) and see what y you get. This gives you an indication of the graph does close to zero. (remember x cannot be zero for this function)

In general, the max/min is found by setting the derivative equal to zero, solving for the variable, and then subbing that back into the original equation.

so

f(x) = 8x - ln(4x)

f'(x) = 8 - 1/x

set this equal to zero, you will get x = 1/8

I will let you find the minimum.

- Calculus -
**Damon**, Thursday, October 16, 2008 at 7:20pmy = 8 x - ln (4x)

y' = 8 -4/x

when is that zero?

4/x = 8

x = 1/2

is that a maximum or a minimum?

y" = 0 +4/x^2

for x>0, y" is positive so it is a minimum

so minimum at x = 1/2

what is the value of the function at that minimum?

y = 8(1/2) - ln 2

4 - ln 2 = about 3.3

**Related Questions**

calculus - Find the points at which y = f(x) = 5x−ln(5x) has a global ...

calculus - Find the points at which y = f(x) = x8−13x has a global maximum...

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...

Calculus - f(x) = sin^2(x/2) defined on the interval [ -5.683185, 1.270796]. ...

Calculus - Find the absolute maximum and absolute minimum values of the function...

Calculus - Answer the following questions for the function f(x) = sin^2(x/3) ...

math - Answer the following questions for the function f(x)=sin^2(x/5) defined ...

Math: Calculus - Answer the following questions for the function f(x)=sin(x/4)^...

Calculus - estimate the absolute maximum and minimum values of f if any, on the ...