A thermodynamic system undergoes a process in which its internal energy increases by 480 J. At the same time, 220 J of work is done by the system. Find the energy transferred to or from it by heat?
I TRIED ADDING 480+220 TO GET 740 but it says it is not the right answer, how close am I plse help?
Heat(in)- Work(out) = Change in internal energy
Heat in = Work + change in Internal energy
You added the right two numbers but should have come up with 700 J
To find the energy transferred to or from the system by heat, we can use the first law of thermodynamics, which states that the change in the internal energy of a system is equal to the heat transferred to the system minus the work done by the system.
Mathematically, it can be expressed as:
ΔU = Q - W
where
ΔU is the change in internal energy,
Q is the heat transferred to the system, and
W is the work done by the system.
In this case, we are given that the change in internal energy (ΔU) is 480 J, and the work done by the system (W) is 220 J.
Substituting these values into the equation, we have:
480 J = Q - 220 J
To find the value of Q, we rearrange the equation:
Q = 480 J + 220 J
Q = 700 J
Therefore, the energy transferred to or from the system by heat is 700 J.
To find the energy transferred to or from the system by heat, you will need to use the First Law of Thermodynamics. According to the First Law, the change in internal energy (ΔU) of a system is equal to the heat transferred (Q) into or out of the system minus the work done (W) by the system:
ΔU = Q - W
In this case, you are given that the internal energy increases by 480 J (ΔU = 480 J) and the work done by the system is 220 J (W = 220 J). You need to find the heat transferred (Q).
Substituting the given values into the equation, we have:
480 J = Q - 220 J
To solve for Q, you need to move the -220 J term to the other side of the equation:
Q = 480 J + 220 J
Q = 700 J
Therefore, the energy transferred to or from the system by heat is 700 J, not 740 J.