Posted by tom on Thursday, October 16, 2008 at 1:42am.
Isothermal expansion
W = integral p dv
p = n R T/v, T constant so
W = n R T integral dv/v
W = n R T ln v from v1 to v2
W = n R T ln(v2/v1)
here
n = 1
R = R =.08206 L atm/mol degK or 8.31 J/mol deg K
Need T, use v2
T = p2 v2/nR = 1*22/1*.082
T = 268 deg K
now we want to use Joules and scientific notaton R
V2 = 22 L = 22* 10^-3 m^3
3400 = 1 * 8.31 * 268 ln (22*10^-3/v)
ln(.022/v)= 1.53
.022/v = 4.6
v = .00478 m^3 = 4.78 Liters
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