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Posted by on Thursday, October 16, 2008 at 1:42am.

One mole of an ideal gas does 3400 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and volume of 22.0 L.
(a) Determine the initial volume in m^3.

i tried using the formula w=integral f/i pdv
3400J= -(1.00atm)(.022m^3Vf-Vi)
i eneded with 1.55 x10^5 but htis is not the right answer. HELP PLS!

  • physics - , Thursday, October 16, 2008 at 5:16am

    Isothermal expansion
    W = integral p dv
    p = n R T/v, T constant so
    W = n R T integral dv/v
    W = n R T ln v from v1 to v2
    W = n R T ln(v2/v1)
    here
    n = 1
    R = R =.08206 L atm/mol degK or 8.31 J/mol deg K
    Need T, use v2
    T = p2 v2/nR = 1*22/1*.082
    T = 268 deg K
    now we want to use Joules and scientific notaton R
    V2 = 22 L = 22* 10^-3 m^3
    3400 = 1 * 8.31 * 268 ln (22*10^-3/v)
    ln(.022/v)= 1.53
    .022/v = 4.6
    v = .00478 m^3 = 4.78 Liters

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