a 5.9 kg bucket of water is raised from a well by a rope.
the acceleration of gravity is 9.81 m/s^2
if the upward acceleration of the bucket is 4.0 m/s^2
what is the force exerted by the rope on the bucket of water. in units of N
force= accelerating force+ weight
= mass*acceleratiion + mg
To find the force exerted by the rope on the bucket of water, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a): F = m * a.
In this case, the mass of the bucket of water is given as 5.9 kg, and the upward acceleration of the bucket is 4.0 m/s^2.
Therefore, we can calculate the force exerted by the rope on the bucket of water as follows:
F = m * a
F = 5.9 kg * 4.0 m/s^2
Multiplying these values together, we get:
F = 23.6 N
So, the force exerted by the rope on the bucket of water is 23.6 Newtons (N).