Posted by ronny on Wednesday, October 15, 2008 at 8:19pm.
ln(M/Mo) = -kt
ln = natural log
M = mass left (not needed)
Mo = original mass (not needed)
(M/Mo) = 0.809
k = 0.693/T(half)
T(half) = 5.73X10^3 years.
ln(M/Mo) = -kt
ln = natural log
M = mass left (not needed)
Mo = original mass (not needed)
(M/Mo) = 0.809
k = 0.693/T(half)
T(half) = 5.73X10^3 years.
ln(M/Mo) = -kt
ln = natural log
M = mass left (not needed)
Mo = original mass (not needed)
(M/Mo) = 0.809
k = 0.693/T(half)
T(half) = 5.73X10^3 years.
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