two men decide to use their cars to pull a truck stuck in mud. They attach ropes and one pulls with a force of 688 N at an angle of 28° with respect to the direction in which the truck is headed, while the other car pulls with a force of 896 N at an angle of 20° with respect to the same direction.
What is the net forward force exerted on the truck in the direction it is headed. in units of N
Resultant in direction it headed = 688cos28 + 896cos20 = Answer in Newtons
To find the net forward force exerted on the truck, we need to determine the horizontal components of the forces applied by both cars and then add them up.
First, let's find the horizontal component of the force applied by the first car:
Horizontal component of the force = Force * cosine(angle)
= 688 N * cos(28°)
Next, let's find the horizontal component of the force applied by the second car:
Horizontal component of the force = Force * cosine(angle)
= 896 N * cos(20°)
Now, we can add up the horizontal components of the forces applied by both cars:
Net forward force = Horizontal component of the first car's force + Horizontal component of the second car's force
Finally, we can calculate the net forward force by plugging in the values and performing the addition:
Net forward force = (688 N * cos(28°)) + (896 N * cos(20°))
Using a calculator, we can evaluate this expression to find the net forward force in units of N.