Posted by Frank on .
Find an equation of the tangent line to the curve at the given point.
y = 3x^2 - x^3, (1,2)
Calculate the slope m by taking the derivative and evaluating it at x = 1
dy/dx = 6x - 3x^2 = 3 at x = 1
The equation for the tangent line will be
(y-2)/(x-1) = m = 3
Write it out in y = mx + b form.
y - 2 = 3x - 3
y = 3x - 1