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March 3, 2015

March 3, 2015

Posted by **Frank** on Tuesday, October 14, 2008 at 10:07pm.

y = 3x^2 - x^3, (1,2)

- calculus -
**drwls**, Wednesday, October 15, 2008 at 8:39amCalculate the slope m by taking the derivative and evaluating it at x = 1

dy/dx = 6x - 3x^2 = 3 at x = 1

The equation for the tangent line will be

(y-2)/(x-1) = m = 3

Write it out in y = mx + b form.

y - 2 = 3x - 3

y = 3x - 1

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