on the assumption that this relation is linear,
you can treat this as being given two ordered pairs in the relation, namely
(40,50 and (80,60), where the first variable is c (chirps) and the second variable is t (time)
so we are looking for t = mc + b (to resemble the familiar y = mx + b linear equation)
slope = (60-50)/(80-40) = 10/40 = 1/4
using m= 1/4 and the point (40,50)
50 = (1/4)(40) + b
b = 40
so you have t = 1/4c + 40
when c = 95
t = (1/4)(95) + 40
= 63.75 degrees
draw a straight line, plot the points
(40,50), (80,60) and (95,t)
then (t-60).(95-80) = (60-5)/(80-40)
(t-60)/15 = 1/4
4t - 240 = 15
t = 63.75
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