calculate the magnitude of the resultant of a pair of 100-km/h velocity vectors that are at right angles to each other. Please help me! thanks!

Dm me now.

You lost.

I would use your right triangle knowledge..

c=sqrt(a^2 + b^2)

thanks! Is approximately 141 km/h correct?

To find the magnitude of the resultant vector of two velocity vectors at right angles to each other, we can use the Pythagorean theorem.

The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the two velocity vectors can be represented by the sides of a right triangle. Let's call the first vector A and the second vector B. The magnitude of vector A is 100 km/h, and the magnitude of vector B is also 100 km/h.

To find the magnitude of the resultant vector, we can use the following formula:

Resultant magnitude = √(A^2 + B^2)

Substituting the given values, we get:

Resultant magnitude = √((100 km/h)^2 + (100 km/h)^2)

Resultant magnitude = √(10000 km^2/h^2 + 10000 km^2/h^2)

Resultant magnitude = √(20000 km^2/h^2)

Resultant magnitude ≈ 141.42 km/h

Therefore, the magnitude of the resultant vector of a pair of 100 km/h velocity vectors that are at right angles to each other is approximately 141.42 km/h.