# CHEMISTRY

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I am having trouble balancing this equation:
Ca(OH){subscript 2} + (NH{subscript 4}){subscript 2} SO{subscript 4} -> CaSO{subscript 4} + NH{subscript 3} + H{subscript 2} O

Response
Ca(OH)2 + (NH4)2SO4 --> CaSO4+ 2NH3 + ?___H2O

I'm still confused...

• CHEMISTRY -

GK did this one and several others for you. GK filled in all the coefficients EXCEPT for one which was left blank. Since you have all the numbers except the one in the blank, it's your job to fill in the blank.

• CHEMISTRY -

Oh, ok. But this one doesn't make sense to me. On the right side of the equation, there are 6 hydrogen, right? But then on the right, there are 8. So how can that work? I don't understand.

• CHEMISTRY -

Wait, I think I have it. Would a "2" go in the blank?

• CHEMISTRY -

There are not 8 H atoms on the right side. There are 6 from the 2NH3 and an unknown number for the H2O because that coefficient was left blank. You are supposed to fill in the blank so the H atoms (and O at the same time) balance. Go back and reread your post because you said, "On the RIGHT side of the equation, there are 6 hydrogen, right? But then on the RIGHT, there are 8." I'm sure you meant LEFT side for one of those rights? I see 10 H atoms on the left side. There are 2 H atoms from Ca(OH)2 and 8 more from the (NH4)2SO4 to make a total of 2 + 8 = 10 H atoms on the left.

• CHEMISTRY -

Right. So am I correct, would the 2 be in that blank?

• CHEMISTRY -

Yes, a 2 goes there. Good work.