Posted by **Anonymous** on Monday, October 13, 2008 at 7:49pm.

I am having trouble balancing this equation:

Ca(OH){subscript 2} + (NH{subscript 4}){subscript 2} SO{subscript 4} -> CaSO{subscript 4} + NH{subscript 3} + H{subscript 2} O

Please help, thanks.

Response

Ca(OH)2 + (NH4)2SO4 --> CaSO4+ 2NH3 + ?___H2O

I'm still confused...

- CHEMISTRY -
**DrBob222**, Monday, October 13, 2008 at 8:01pm
GK did this one and several others for you. GK filled in all the coefficients EXCEPT for one which was left blank. Since you have all the numbers except the one in the blank, it's your job to fill in the blank.

- CHEMISTRY -
**Anonymous**, Monday, October 13, 2008 at 8:04pm
Oh, ok. But this one doesn't make sense to me. On the right side of the equation, there are 6 hydrogen, right? But then on the right, there are 8. So how can that work? I don't understand.

- CHEMISTRY -
**DrBob222**, Monday, October 13, 2008 at 8:21pm
There are not 8 H atoms on the right side. There are 6 from the 2NH3 and an unknown number for the H2O because that coefficient was left blank. You are supposed to fill in the blank so the H atoms (and O at the same time) balance. Go back and reread your post because you said, "On the RIGHT side of the equation, there are 6 hydrogen, right? But then on the RIGHT, there are 8." I'm sure you meant LEFT side for one of those rights? I see 10 H atoms on the left side. There are 2 H atoms from Ca(OH)2 and 8 more from the (NH4)2SO4 to make a total of 2 + 8 = 10 H atoms on the left.

- CHEMISTRY -
**DrBob222**, Monday, October 13, 2008 at 8:29pm
Yes, a 2 goes there. Good work.

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