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chemistry

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Enormous numbers of microwave photons are needed to warm macroscopic samples of matter. A portion of soup containing 177 g of water is heated in a microwave oven from 20degrees Celsius to 98 degrees Celsius, with readiation of wavelength 1.55x10^-2m. How many photons are absorbed by the water in the soup?

  • chemistry -

    Calculate q for the heat required to heat the soup.
    q = mass x specific heat H2O x delta T.
    q = ?? in Joules.
    Then use E = hc/wavelength to determine the energy per photon. Go from there. Post your work if you get stuck. Check my thinking.

  • chemistry -

    ok. whew. just put in my answer into webassign and i got it correct.

    Ill show the example with the numbers I was given. That way you can actually do the problem with your numbers.

    I found the way to do this at the link below.

    so my water mass was 360 g
    my temp went from 28C to 93C
    the radiation of wavelength is 1.55 x 10-2 m (same)

    k so the first thing to do is find the work needed.
    Q=mcΔT
    this is mass times (4.184J/g°C) ΔT. so (360)(4.184)(93-28) = 97905.6 J. The 4.184 changes things to Angstroms. The overall equation will have the units Joules.

    k so we also have the equations
    E'=hv and c=λv
    h = 6.626 x 10^-34
    c = 3 x 10^8
    solve and replace so that somehow you get this
    Q (97905.6 J) / (hc/1.55 x 10^-2)

    so 97905.6/((6.626e-34)(3e8)/(1.55e-2))
    I got 7.6e27
    webassign verified it.

  • your mom -

    its so easy

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