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December 20, 2014

December 20, 2014

Posted by **Sara** on Monday, October 13, 2008 at 7:27pm.

- CHemistry Help pleaseee -
**DrBob222**, Monday, October 13, 2008 at 7:41pmWrite the equation.

2C2H2 + 5O2 ==> 4CO2 + 2H2O

2.Use PV = nRT to determine n (# mols) O2 in the larger tank. No T is given; therefore, pick any T and use that T throughout the calculations.

3. Using the coefficients in the balanced equation, convert mols O2 to mols C2H2.

4. Now use PV = nRT to calculate P of the smaller tank for C2H2.

- CHemistry Help pleaseee -
**Sara**, Monday, October 13, 2008 at 7:46pmThe T is have to use is 25C,and im trying to find the number of moles of oxygen first, so

PV= nRT

(115 atm)(6L)= n(0.08206)(25)

bUH IM NOT SURE IF I NEED TO CONVERT THE PRESSURE OR LITRES TO SOMETHING ELSE

- CHemistry Help pleaseee -
**DrBob222**, Monday, October 13, 2008 at 7:55pmP is in atmospheres. V is in liters. T is in Kelvin (Kelvin = 273 + C or 298 for 25 C). R is 0.08205 L*atm/mol*K.

- CHemistry Help pleaseee -
**Sara**, Monday, October 13, 2008 at 7:58pmOMg thank you soo much

- CHemistry Help pleaseee -
- CHemistry Help pleaseee -
**GK**, Monday, October 13, 2008 at 8:11pmThe balanced chemical reaction is:

2C2H2 + 5O2 --> 4CO2 + 2H2O

The mole ratio of C2H2 to O2 is 2 : 5. Rearranging the Ideal Gas Law, we get:

n = PV / RT or

Let n1 = P1V1/RT (moles of C2H2)

and n2 = P2V2/RT (moles of O2

n1/n2 = P1V1/RT * RT/P2V2

Simplifying,

n1/n2 = P1V1 / P2V2

n1/n2 = (P1/P2)(V1/V2)

Substitute:

n1 = moles of C2H2 (acetylene) = 2

n2 = moles of O2 = 5

P1 = pressure of acetylene (unknown)

P2 = pressure of O2

V1 = volume of C2H2

V2 = volume of O2

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