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September 17, 2014

September 17, 2014

Posted by **Carl** on Monday, October 13, 2008 at 6:59pm.

Find f'(x)

- Calculus -
**Carl**, Monday, October 13, 2008 at 7:07pmnvm it's 3/5

- Calculus -
**Damon**, Monday, October 13, 2008 at 7:34pmsay d/dx (g) = 9 x^4

then g = (9/5)x^5 + constant

so

f(3x^5) = (9/5) (3x^5)^5 + constant

f(x) = (9/5) x^5 + c

f'(x) = 9x

- Calculus -
**Damon**, Monday, October 13, 2008 at 7:35pmI mean 9 x^4

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