Posted by **solexgirl12** on Monday, October 13, 2008 at 4:30pm.

"If a skier coasts down a slope at an angle of 24 degrees below the horizontal, what is her acceleration if the force of friction is negligible?"

I must have done this question 15 times, and still can't get the right anwser. Can anyone help me?

- 12th grade Physics -
**Damon**, Monday, October 13, 2008 at 4:44pm
say she has mass m

there is a gravitational force down on her = m g

that force has a component normal (perpendicular) to the snow)=mg cos 24

there is an equal and opposite force up from the snow = mg cos 24

because there is no acceleration into or out of the snow.

HOWEVER, that gravitational force has another component down the slope = m g sin 24

There is no equal and opposite force to resist that because she is free to accelerate down the slope.

so

F = m a = m g sin 24

so

a = g sin 24

g is about 9.8 m/s^2

and sin 24 is about .407

- 12th grade Physics -
**solexgirl12**, Monday, October 13, 2008 at 11:24pm
Thank you so much; once I drew my slope levels correctly, it was no problem. Thanks again!

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