Posted by **Geroge** on Sunday, October 12, 2008 at 10:48pm.

A certain density curve looks like an interverted letter V. The first segment goes fro the point (0,0.6) to the point (0.5,1.4). The segment goes from (0.5.1.44) to (1,0.6).

(a) Sketch the curve. Verify that the area under the curve is 1, so that it is a valid density.

-- Okay, I tried graphing that on my calculator and it came out looking weird... my highest bar on the histogram is 3. How do you verfiy the area under the curve? And how am I suppose to determine the median ? Do I use ALL of those numbers?

Please help and thank you!

## Answer This Question

## Related Questions

- Statistics - A density curve like an inverted letter "V" The first segment goes ...
- Calculus - Consider line segments which are tangent to a point on the right ...
- calculus - Consider line segments which are tangent to a point on the right half...
- Geometry - Theorem: A line parallel to one side of a triangle divides the other...
- Calculus - Find the area cut off by x+y=3 from xy=2. I have proceeded as under: ...
- Calculus - For the parabola y^2=4px, where p, the focal length, is a constant, ...
- Another graph - How do I make a graph of f'(-1) = f'(1) = 0, f'(x) > 0 on (-1...
- geometry - In triangle abc, point B is on segment ab, and point E is on segment ...
- math - Given: segment AC and segment BD bisect each other at E prove: E is the ...
- Stat - Remeber that it is areas under a density curve, not the height of the ...

More Related Questions