Posted by Bridget on Sunday, October 12, 2008 at 6:46pm.
so im not that good with word problems so... here it goes.
Nadine has 7 more nickles than Delano has dimes. If Delano gives Nadine 4 of his dimes, then Delano will have the same amountof money as Nadine. How much money do they have together, assuming Nadine only has nickles and Delano only has dimes?

Algebra 1  Damon, Sunday, October 12, 2008 at 6:57pm
dimes = d
nickles = (d+7)
then later
(d4)(.1) = (d+7)(.05)+4(.1)

Algebra 1  Bridget, Sunday, October 12, 2008 at 7:02pm
would that be the same as
.05(d+7)=(d4).1 ?

Algebra 1  Damon, Sunday, October 12, 2008 at 7:04pm
no, you need to credit Nadine with 4 dimes (4)(.1)

Algebra 1  Bridget, Sunday, October 12, 2008 at 7:16pm
oooh!!! ok, thank you!!! so then i would get
.1d  .4 = .05d + .35 + .4
.1d  .4 = .05d + .75
.05d  .4 = .75
.05d = 1.15
d = 23
right???

Algebra 1  Damon, Sunday, October 12, 2008 at 7:21pm
looks good

Algebra 1  erick, Tuesday, October 14, 2008 at 8:44pm
3y+4=8y4+6y
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