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October 1, 2014

October 1, 2014

Posted by **Bridget** on Sunday, October 12, 2008 at 6:46pm.

Nadine has 7 more nickles than Delano has dimes. If Delano gives Nadine 4 of his dimes, then Delano will have the same amountof money as Nadine. How much money do they have together, assuming Nadine only has nickles and Delano only has dimes?

- Algebra 1 -
**Damon**, Sunday, October 12, 2008 at 6:57pmdimes = d

nickles = (d+7)

then later

(d-4)(.1) = (d+7)(.05)+4(.1)

- Algebra 1 -
**Bridget**, Sunday, October 12, 2008 at 7:02pmwould that be the same as

.05(d+7)=(d-4).1 ?

- Algebra 1 -
**Damon**, Sunday, October 12, 2008 at 7:04pmno, you need to credit Nadine with 4 dimes (4)(.1)

- Algebra 1 -
**Bridget**, Sunday, October 12, 2008 at 7:16pmoooh!!! ok, thank you!!! so then i would get

.1d - .4 = .05d + .35 + .4

.1d - .4 = .05d + .75

.05d - .4 = .75

.05d = 1.15

d = 23

right???

- Algebra 1 -
**Damon**, Sunday, October 12, 2008 at 7:21pmlooks good

- Algebra 1 -
**Bridget**, Sunday, October 12, 2008 at 7:23pmok, thank you sooo much!!! :)

- Algebra 1 -
- Algebra 1 -
**erick**, Tuesday, October 14, 2008 at 8:44pm-3y+4=8y-4+6y

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