Posted by **Bridget** on Sunday, October 12, 2008 at 6:46pm.

so im not that good with word problems so... here it goes.

Nadine has 7 more nickles than Delano has dimes. If Delano gives Nadine 4 of his dimes, then Delano will have the same amountof money as Nadine. How much money do they have together, assuming Nadine only has nickles and Delano only has dimes?

- Algebra 1 -
**Damon**, Sunday, October 12, 2008 at 6:57pm
dimes = d

nickles = (d+7)

then later

(d-4)(.1) = (d+7)(.05)+4(.1)

- Algebra 1 -
**Bridget**, Sunday, October 12, 2008 at 7:02pm
would that be the same as

.05(d+7)=(d-4).1 ?

- Algebra 1 -
**Damon**, Sunday, October 12, 2008 at 7:04pm
no, you need to credit Nadine with 4 dimes (4)(.1)

- Algebra 1 -
**Bridget**, Sunday, October 12, 2008 at 7:16pm
oooh!!! ok, thank you!!! so then i would get

.1d - .4 = .05d + .35 + .4

.1d - .4 = .05d + .75

.05d - .4 = .75

.05d = 1.15

d = 23

right???

- Algebra 1 -
**Damon**, Sunday, October 12, 2008 at 7:21pm
looks good

- Algebra 1 -
**erick**, Tuesday, October 14, 2008 at 8:44pm
-3y+4=8y-4+6y

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