The perimeter of a rectangle is 90 meters. The length is 9 meters more than twice the width. Find the dimensions.

I need the length and the width.

Thanks!

width = w

length = (9+2w)
90 = 2 (w + (9+2w) )
45 = 3 w + 9
36 = 3w
onward :)

ah, 2x + (4x+18) = 90

x = 12

A rectangle is 5 times longer then it is wide. If perimeter of the rectangle is 222m. What are its dimensions

To find the dimensions of the rectangle, we need to set up an equation based on the given information and then solve for the values of length and width.

Let's denote the width of the rectangle as "w". According to the given information, the length is 9 meters more than twice the width, which can be expressed as "2w + 9".

The formula for the perimeter of a rectangle is given by: P = 2(l + w), where P represents the perimeter, l represents the length, and w represents the width.

Substituting the given values, we have: 90 = 2(2w + 9 + w)

We can simplify the equation by distributing the 2 on the right side: 90 = 2(3w + 9)

Now, let's solve the equation step by step:

Step 1: Distribute the 2 on the right side: 90 = 6w + 18

Step 2: Move 18 to the left side by subtracting it from both sides: 90 - 18 = 6w + 18 - 18

Simplifying: 72 = 6w

Step 3: Divide both sides by 6 to isolate the variable w: 72/6 = 6w/6

Simplifying: 12 = w

Therefore, the width of the rectangle is 12 meters.

Now, we can substitute the value of the width (w = 12) into the expression for the length (2w + 9) to find its value:

Length = 2w + 9 = 2(12) + 9 = 24 + 9 = 33 meters

So, the length of the rectangle is 33 meters.

In summary, the dimensions of the rectangle are:

Length = 33 meters
Width = 12 meters