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September 18, 2014

September 18, 2014

Posted by **Shawn** on Sunday, October 12, 2008 at 4:40pm.

4a^2/(a-b)-(4b^2-8ab)/(b-a)

I have the answer as 4(a+b)^2/(a-b)

or should it be 4(a-b)^2/(a-b)

Responses

Math problem check - bobpursley, Sunday, October 12, 2008 at 4:23pm

just the numerator..

4a^2-8ab + 4b^2, right?

4(a-b)^2

Now does that reduce with the denominator?

Math problem check - Shawn, Sunday, October 12, 2008 at 4:28pm

Okay I have the answer as 4(a-b) is that right

Math problem check - Shawn, Sunday, October 12, 2008 at 4:37pm

What about

4a^2/(a-b)-(4b^2-8ab)/(b-a)

I thought that you would multiple the second part of the equation by -1

-(4b^2-8ab)/(b-a)

to get the common LCD of a-b

So I thought the equation would be 4a^2/(a-b) + (4b^2 + 8ab)/(a-b)

I have the answer as 4(a+b)^2/(a-b)

- math check question -
**bobpursley**, Sunday, October 12, 2008 at 4:46pmYou are wrong.

THe second part only..

-4(b^2-2ab)/(b-a)

+4(b^2-2ab)/(a-b)

Your answer is still wrong.

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