Posted by Shawn on .
Subtract and Simplify:
4a^2/(ab)(4b^28ab)/(ba)
I have the answer as 4(a+b)^2/(ab)
or should it be 4(ab)^2/(ab)
Responses
Math problem check  bobpursley, Sunday, October 12, 2008 at 4:23pm
just the numerator..
4a^28ab + 4b^2, right?
4(ab)^2
Now does that reduce with the denominator?
Math problem check  Shawn, Sunday, October 12, 2008 at 4:28pm
Okay I have the answer as 4(ab) is that right
Math problem check  Shawn, Sunday, October 12, 2008 at 4:37pm
What about
4a^2/(ab)(4b^28ab)/(ba)
I thought that you would multiple the second part of the equation by 1
(4b^28ab)/(ba)
to get the common LCD of ab
So I thought the equation would be 4a^2/(ab) + (4b^2 + 8ab)/(ab)
I have the answer as 4(a+b)^2/(ab)

math check question 
bobpursley,
You are wrong.
THe second part only..
4(b^22ab)/(ba)
+4(b^22ab)/(ab)
Your answer is still wrong.