Friday

November 28, 2014

November 28, 2014

Posted by **Lucy** on Sunday, October 12, 2008 at 2:00pm.

So far I have the center at (-1,-2) and part of the equation is (y+2)^2 - (x+1)^2 but do not know how to figure a^2, b^2, or c^2.

Help please....

- Pre-Calculus -
**bobpursley**, Sunday, October 12, 2008 at 2:27pmHmmm. I dont know what you mean by c.

(y+2)^{2}/a^{2}-(x+1)^{2}/b^{2}= 1

You have two points for x,y, that should give you two equation to solve for a, b.

- Pre-Calculus -
**Damon**, Sunday, October 12, 2008 at 2:31pmcenter to vertex = a = 3

center to focus = sqrt(a^2+b^2) = 5

so 9+b^2 = 25

b = 4

**Answer this Question**

**Related Questions**

pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...

math - the vertices are at (2,1) and (2,7) and focus is at (2,*) write the ...

Hyperbolas - Find the equation of the hyperbola whose vertices are at (-1,-5) ...

Pre-calculus-ck answers - Identify the graph of the equation 4x^2-25y^2=100. ...

Math Help PLEASE! - Find the equation of the hyperbola whose vertices are at (-1...

Pre-calc - Heres the equation: (x^2)-(4y^2)-(4x)+(24y)-(36)=0 Your supposed to ...

Pre-calculus - For the ellipse with equation 5x^2+64y^2+30x+128y-211=0, find the...

algebra - a hyperbola has vertices (+-5,0) and one focus (6,0) what is the ...

algebra - Can someone please help... a hyperbola has vertices (+-5,0) and one ...

math30 - The equation of the hyperbola is (x-3)^2/4 - (y+1)^2/16 =-1. What is ...