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December 29, 2014

December 29, 2014

Posted by **Lucy** on Sunday, October 12, 2008 at 2:00pm.

So far I have the center at (-1,-2) and part of the equation is (y+2)^2 - (x+1)^2 but do not know how to figure a^2, b^2, or c^2.

Help please....

- Pre-Calculus -
**bobpursley**, Sunday, October 12, 2008 at 2:27pmHmmm. I dont know what you mean by c.

(y+2)^{2}/a^{2}-(x+1)^{2}/b^{2}= 1

You have two points for x,y, that should give you two equation to solve for a, b.

- Pre-Calculus -
**Damon**, Sunday, October 12, 2008 at 2:31pmcenter to vertex = a = 3

center to focus = sqrt(a^2+b^2) = 5

so 9+b^2 = 25

b = 4

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