Sunday

August 31, 2014

August 31, 2014

Posted by **Erica** on Sunday, October 12, 2008 at 1:42pm.

I don't understand any of the responses.

You have to assume in this case the wind retards and assists with the same force, which is not usually true.

Vrg=Vrgs+Vwind

where Vrg is net velocity relative to ground, Vrgs is velocity relative to ground in still conditions, and Vwind is the velocity of the wind.

Vrgs=32

33km/time=32km/hr-Speedwind

63km/time=32km/hr+speed wind.

add the equations...

33+63)km/time=64km/hr

then time= 96/64 hr

Now solve for speed of wind in the first equation..

33km/time=32km/hr-speedwind.

- Math word problem -
**Writeacher**, Sunday, October 12, 2008 at 2:04pmErica, David, Shawn, or whoever,

Your question has been answered below. If there is**a particular part**of the response that you don't understand, please let the math teachers know what that is. To simply say you don't understand doesn't give them much to work with.

- Math word problem -
**Erica**, Sunday, October 12, 2008 at 2:39pmI am having problems with this part:

add the equations...

33+63)km/time=64km/hr

then time= 96/64 hr (I know this is 1.5)

Now solve for speed of wind in the first equation..

(is it 33km/1.5 =22)

33km/time=32km/hr-speedwind.

- Math word problem -
- Math word problem -
**bobpursley**, Sunday, October 12, 2008 at 3:14pmI assume you can add the equations.

Then solve for time.

Now to solve for wind speed

33/1.5=32-speedwind

33/1.5 -32=-speedwind

I assume you can solve that.

- Math word problem -
**Shawn**, Sunday, October 12, 2008 at 3:21pmThank you I have the answer as 10km/h.

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