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Posted by **Shawn** on Sunday, October 12, 2008 at 12:25pm.

(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)

I do know that (t^2-t-56) can be factored out to (t-8)(t+7) so I have the equation as (t+24/(t-8)(t+7) +7(t+7)/(t-8)(t+7)-3(x-8)/(t-8)(t+7) is this correct ot what am I doing wrong?

- Mathematics -
**Writeacher**, Sunday, October 12, 2008 at 12:44pmAssistance needed.

- a problem -
**Shawn**, Sunday, October 12, 2008 at 12:46pmSolve:

(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)

How do I solve this problem

- a problem -
**bobpursley**, Sunday, October 12, 2008 at 12:48pmthe common denominator is (t-8)(t+7)

so multipy both sides by

(t-8)(t+7)

(t-24) + 7(t+7)=3(t-8)

solve for t.

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