Sunday
September 21, 2014

Homework Help: chemistry

Posted by starlight on Sunday, October 12, 2008 at 12:08pm.

last check:
(c) A wine cooler contains 4.5% ethanol by mass. Assuming that only the alcohol burns in oxygen, how many grams of wine cooler need to be burned to produce 3.12 L of CO2 (d = 1.80 g/L at 25C, 1 atm pressure) at the conditions given the density?

1 C2H5OH + 3 O2 = 2 CO2 + 3 H2O
3.12 L CO2 * (1.80 g / 1 L) = 5.62g CO2
5.62 g CO2 * (1 mol / 44 g CO2) = 0.128 mol of CO2
0.128 mol CO2 * (1 mol of C2H5OH / 2 mol of CO2) = 0.064 mol C2H5OH
0.064 mol of C2H5OH * (46 g / 1 mol) = 2.944g C2H5OH
2.944g C2H5OH * (100 / 4.5) =
65.42 g of wine cooler

Is this right? thanks

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