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November 22, 2014

November 22, 2014

Posted by **Shawn** on Sunday, October 12, 2008 at 11:35am.

1/C=1/C1 + 1/C2 for C1

This multiple choice and the listed answers are:

a.)C1= CC2/(C2-C)

b.)C1= C-C2/C

c.)C1= C+C2/CC2

d.)C1= C+C2/C2

- Solve -
**drwls**, Sunday, October 12, 2008 at 11:39amShow us your attempt to do the algebra. You won't learn a thing is you ask us to just do your work for you.

The first step would be to write

1/C1 = 1/C - 1/C2 = (C2 - C)/(C*C2)

The take the reciprocal of both sides.

Very nearly the same question was posted last night. Was it by you?

- Solve -
**Shawn**, Sunday, October 12, 2008 at 11:48amYes, I am still having problems with this problem. I understand this part

1/C1 = 1/C - 1/C2

but I don't understand this part:

(C2 - C)/(C*C2)

- Solve -
**Shawn**, Sunday, October 12, 2008 at 11:58amOkay I understand it now I have to make them have the same denominators so I multiply 1/C by the numerator and denominator by C2 so it would be C2/(C2*C)

and the other part is 1/C2 times C which would be C/(C2*C) which would make the problem 1/C1= C2-C/(C2*C)

what do I do next?

- Solve -
- Solve -
**drwls**, Sunday, October 12, 2008 at 2:53pmFlip both fractions upside down, as i indicated earlier.

You will be using the fact that if a/b = c/d, then b/a = d/c

You will end up with the equation for C1

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