Posted by Alli on Sunday, October 12, 2008 at 10:23am.
No. If you want work W in Joules, that would be
W, J = (force, N)*(distance, m)
= (mass, kg)*(g,m/s^2)*(distance,m)
= 0.001 (mass, g)*9.8 m/s^2*(distance,m)
The numerical factor would be 0.0098, slightly less than 0.01
right, so in other words I would round it . . . . .
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