Wednesday

March 4, 2015

March 4, 2015

Posted by **Beth** on Sunday, October 12, 2008 at 7:30am.

n=(2J+1)exp(-(BJ(J+1))/(KT))

where T, B and K are constants

- Math -
**drwls**, Sunday, October 12, 2008 at 8:14amThis questions was posted and answered about a day ago. If you posted it, look for previous posts with your name.

**Answer this Question**

**Related Questions**

Maths - Rearrange for T and J; n=(2J+1)exp(-(BJ(J+1))/(KT)) where B and K are ...

Maths - Transform the following relationships/funtions into linear form and ...

Calculus II - What is sin(i) -- (sin of the imaginary number, i) What is cos(i...

Math/Calculus - How would I evaluate the following integral by using integration...

Maths - P=(2J+1)exp(-(BJ(J+1))/kT) where B, k and T are constants a. Show that ...

Physics/Math - A can of sardines is made to move along an x axis from x1 = 0.2 m...

(expi)^i - This question is not well defined. By 'expi' do you mean exp(i)? In ...

Re: Physics/Math - A can of sardines is made to move along an x axis from x1 = ...

calc: arc length - find the exact length of this curve: y = ( x^3/6 ) + ( 1/2x...

maths-complex numbers - by using the substitution w = z^3, find all the ...