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October 22, 2014

October 22, 2014

Posted by **Shawn** on Sunday, October 12, 2008 at 12:25am.

- Math another problem -
**drwls**, Sunday, October 12, 2008 at 12:43amSubtract 1/C2 from each side.

1/C1 = 1/C - 1/C2 = (C2-C)/(C*C2)

Now turn both fractions upside down. This is called "taking the reciprocal of both sides"

C1 = C*C2/(C2 - C) = 1/[(1/C) - (1/C2)]

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