Thursday
October 2, 2014

Homework Help: physics

Posted by Vishnu on Saturday, October 11, 2008 at 6:00pm.

An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm is 68.7 cm long and has a mass of 4.69 kg. What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor?

Torque = massball x length + massarm x length/2

= 4.33 kg x 0.687 m + 4.69 kg x 0.687 m/2

= 7.66472 x 1.374

= 10.5 N

Why is my answer incorrect?

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