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September 16, 2014

September 16, 2014

Posted by **Lucy** on Saturday, October 11, 2008 at 5:09pm.

Answer: -401.07 degrees

- Pre-Calculus-check answers -
**drwls**, Saturday, October 11, 2008 at 5:52pm-401.07 degrees is the same as -41.07 degrees. That would be in the fourth quadrant. There should have been a figure associated with this problem showing the direction and place that the arc was located.

Let's just consider the size of the subtended angle.

An 8 cm arc on a 15 cm radius is 8/15 radian or

(8/15)(180/pi) = 96/pi = 30.56 degrees

I have no idea how you or your textbook came up with -401.07 degrees

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