11th grade math algebra 2 trig
posted by Nick .
the tens digit of a two digit number is 6 more than the units digit. the number is 36 more than the number when the digits are reversed/ what is the number?

This is algebra II?
Let AB be the number.
A6=B
A*10+B36=B(10)+A 
when i solve for the variables i cancel everything and i don't get an answer

i solved for the longer equation and got a=b+4
i put that in the smaller equation and got b2=b
iam confused 
I'm just really confused about everything

There is no solution to your question
the only possible cases of a two digit number where the tens digit is 6 more than the units digit are:
60, 71, 82, and 93
the numbers with the digits reversed would be
06, 17, 28, and 39
in each case the difference would be 54, never 36 
5(45sin+cos2)y+344=

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