Posted by **Kim K** on Thursday, October 9, 2008 at 8:42pm.

Consider the following three vectors: a = 3i + 4j ; b = pi + 2j ; c = mi + nj , where

m, n and p are constants. If:

a + b = 9i + 6j

a.c = 10

b x c = 2k

Show that p = 6, and determine values for m and n.

i got the p=6

as for the rest...what i did so far

b x c = 2k

so (6i x nj) + 2j x mi

6nk + 2mk = 2k...cancel out k's and simplify by dividing through by 2

so

3n + 1m = 1

___

a.c = 10

so

3i.mi + 4j.nj = 10

3m + 4n = 10

i would say solve simulatneously...but

when i do that, the answer doesn't come out to

m = 2 and n = 1

instead, i get m=3.2 and n=1.4

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