Posted by Cynthia on Thursday, October 9, 2008 at 5:11pm.
From the given circle equation you would have to know that its centre is (0,0) and its radius is √40
Notice that both A and B satisfy the equation of the circle, so A and B lie on the circle and AB is indeed a chord.
In a) you are probably expected to illustrate the property that the right-bisector of any chord passes through the centre of the circle.
You claim you did that, ok.
BTW, what did you get for the distance from the centre to chord AB ?
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