Posted by Vishnu on Thursday, October 9, 2008 at 4:42pm.
Looking at the ball and his arm, and assuming the mass of the arm is at the center of the arm...
torque=massball*length + massarm*length/2
Should the lenght be in centimetres or metres and the mass of the ball in kilograms?
Normally, it does not matter if you place units on your answer. Standard form is n-meters.
What is the magnitude of the torque about his shoulder if he holds his arm straight, but 46.6° below horizontal?
gOOD QUESTION
i would think it would be,
torque=massball*length*sin46.6 + massarm*length/2cos*46.6
Related Questions
physics - An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm ...
Physics - An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm ...
physics - An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm ...
physics - An athlete at the gym holds a 5.29 kg steel ball in his hand. His arm ...
physics - An athlete at the gym holds a 1.2 kg steel ball in his hand. His arm ...
physics - An athlete at the gym holds a 1.2 kg steel ball in his hand. His arm ...
physics - An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm ...
physics - An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm ...
physics - An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm ...
Physics!! - An athlete at the gym holds a 5.54kg steel ball in his hand. His arm...
For Further Reading
