Saturday
March 25, 2017

Post a New Question

Posted by on .

An athlete at the gym holds a 4.33 kg steel ball in his hand. His arm is 68.7 cm long and has a mass of 4.69 kg. What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor?

  • physics - ,

    Looking at the ball and his arm, and assuming the mass of the arm is at the center of the arm...

    torque=massball*length + massarm*length/2

  • physics - ,

    Should the lenght be in centimetres or metres and the mass of the ball in kilograms?

  • physics - ,

    Normally, it does not matter if you place units on your answer. Standard form is n-meters.

  • physics - ,

    What is the magnitude of the torque about his shoulder if he holds his arm straight, but 46.6° below horizontal?

  • physics - ,

    gOOD QUESTION
    i would think it would be,
    torque=massball*length*sin46.6 + massarm*length/2cos*46.6

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question