Thursday
August 21, 2014

Homework Help: Phys. pendulum

Posted by KimK on Thursday, October 9, 2008 at 12:26pm.

A pendulum consists of a mass of 3 kg tied to the end of a string of length 1.5 m.
The pendulum is initially held at angle of 45o with the vertical and the pendulum
is released. At the instant the mass passes through its lowest position it is 2 m
above the ground and the string breaks.


Show that the speed of the mass as it passes through its lowest position is
2.93 m/s.
(ii) Find the tension in the string just before it breaks.
(iii) Find the time it takes for the mass to hit the ground.
(iv) Find the horizontal distance traveled by the mass after the string breaks.

__________ so far, this is what i did
m = 3 kg
l = 1.5m
angle = 45o



i said, F=ma which is 3 x 9.81 = 29.43

mv^2 / r = 29.43sin45

since the height is 2m above the ground at the lowest point, r would be 1m...right?

so

3v^2 = 25

v = 2.89

however, the ans is suppose to be 2.93

for 2!

i said that Tension (T) - Weight (W) = mv2/r

found the weight by w=mg which gave 29.43
T - 29.43 = 8.79

i got 38 and the ans is suppose to be 46

i think something is wrong with the reasoning.l..HLP!

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