Posted by Ryan on Wednesday, October 8, 2008 at 10:57pm.
How much heat must be removed from the 25.6 g H2O @ 21.0.0 C to move it to 0.0 C.
That will be
q = heat to be removed = mass x specific heat water x delta T.
q = 25.6 g x 4.18 x 21.0 = about 2000 J (but you need to do it exactly).
Then 2000 J x 1 g/heat fusion = grams ice.
You are given the heat of fusion in kJ/mol. You must change that to J/g so it will fit the remainder of the problem. It's approximately 334 J/g but you need to verify that. Post your work if you get stuck.
it worked perfectly, thank you so much
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