First some house cleaning.
1. Its CuSO4 and not CUSO4.
2. I presume your use of clear means it is colorless. There is no such color as clear. Colorless means it has no color. Clear means it is not turbid. A solution can be blue and clear or blue and turbid or colorless and turbid or colorless and clear.
3. Are these solids. In solution?
4. OK. The two blue solution will be the two copper solutions. If in solid form the blue crystals are the copper containing materials. The two colorless solutions will be the CaCl2 and NH4OH.
5. Addition of NH4OH to Cu solutions causes a deep blue color to form. CaCl2 added to the copper solution--nothing.
I'll leave the remainder for you. None of this will differentiate between the two copper solutions. If they are in solid form we could differentiate.
both of the BLUE SOLUTIONS were in liquid form, and we have to figure out a way to differenciate the two
sorry, my friend is Graymon, i forgot to change the name when i posted before
A small correction. CaCl2 added to CuSO4 will form CaSO4 which is a white ppt and relatively insoluble in water.It is listed in most tables as being slightly soluble. Cu(NO3)2 and CaCl2 don't produce CaSO4 and Ca(NO3)2 is quite soluble. I'll be happy to look over your procedure if you want to type it in.
ok ill post it a little bit later this weekend, will you be available?