Thursday

July 31, 2014

July 31, 2014

Posted by **allison** on Wednesday, October 8, 2008 at 7:22pm.

please help me get started ...tnk u

- plz integrate -
**bobpursley**, Wednesday, October 8, 2008 at 7:24pmI would do partial fractions.

- plz integrate -
**Damon**, Wednesday, October 8, 2008 at 7:55pmassume you mean

(1+u) du /(3u+2u^2)

which is

(1+u) du/[u(3+2u)]

which is

1 du/[u(3+2u)] + u du/[u(3+2u)]

now let's see if we can expand 1/[u(3+2u)]

into

a/u + b/(3+2u) = 1/ [u(3+2u)]

a(3+2u) + b(u) = 1

3 a = 1 so a = 1/3

2a + b = 0 so b = -2/3

so we have

1/[u(3+2u)] = (1/3)/u - (2/3)/(3+2u)

so the integral now is

(1/3)du/u -(2/3)du/(3+2du) +du/(3+2u)

or

(1/3)du/u +(1/3) du/(3+2u)

ok from there?

**Related Questions**

PLZ integrate - integrate cos^3x dx tnk U

Integral calculus - Please do help solve the followings 1) Integrate e^4 dx 2) ...

calculus - 1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (...

Calc 1 - integrate from 0 to pi/4 (sec^2x)/((1+7tanx)^2)^1/3 integrate form pi^2...

integrate - integrate du/3u and integrate x/x^2 dx it might be simple...i just ...

Calculus - 6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b...

calculus 2 - Justify, with a written explanation or a mathematical reasoning ...

calculus help please - dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,-1 into ...

Calculus AB - Please help me integrate this equation using partial fractions: ...

MATHS...PLEASE HELP - what do you get when you: integrate 10sin^4xcosx dx when ...