Posted by **allison** on Wednesday, October 8, 2008 at 6:38pm.

integrate du/3u

and integrate

x/x^2 dx

it might be simple...i just need a head start...tnx

- integrate -
**allison**, Wednesday, October 8, 2008 at 6:39pm
do i use the subsitution rule?

- integrate -
**Damon**, Wednesday, October 8, 2008 at 8:21pm
du/3u = (1/3) du/u

which is (1/3)[ ln u + ln constant ]

--> (1/3) ln ( c u)

c = 3 works

so

(1/3) ln 3u + constant

x/x^2 = 1/ x

so

dx/x --> ln x + constant

I think x^1*x^-2 = x^-1 = 1/x

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