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August 28, 2014

August 28, 2014

Posted by **allison** on Wednesday, October 8, 2008 at 6:15pm.

2u du /u-2+2u^2

so i used subsitution rule?

or can i used integration by parts and how? thanks in adnvace

- integrate -
**drwls**, Wednesday, October 8, 2008 at 8:18pmIs all of u -2 +2u^2

a denominator?

That is (2u-1)(u+1)

So you would be integrating

2u/[(2u-1)(u+1)]

The method of partial fractions can be used.

See

http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html

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