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December 20, 2014

December 20, 2014

Posted by **nadine** on Wednesday, October 8, 2008 at 12:03pm.

x^2-8x+16 would this be the right way

8x^3+16 to start

- Math -
**Reiny**, Wednesday, October 8, 2008 at 1:35pmOH NO, you cannot add unlike terms

x^2 - 8x + 16

=(x-4)(x-4)

check it by expanding

BTW, you did not have an "equation".

did you have x^2 - 8x + 16 = 0 ?

then (x-4)(x-4)=0

x = -4

- Math -
**Reiny**, Wednesday, October 8, 2008 at 2:12pmI obviously meant x = 4 (not -4)

(that "oldtimers" syndrome hitting again)

- Math -
- Math -
**drwls (quitting)**, Wednesday, October 8, 2008 at 1:36pmThe factors of x^2 - 8x + 16 are (x-4)(x-4)

You did not write an equation.

If you had written x^2 -8x + 16 = 0, which IS an equation, the answer would be x = 4. That would be the only answer, since both factors are zero when x = 4.

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