Posted by Tri on Wednesday, October 8, 2008 at 5:17am.
Can't you calculate the limiting reagent.
Starting with 6 mols B, how many mols A would you need for 100% reaction? That would be 6 mols B x (4 mols A/1 mol B) = 24 mols A and you don't have that much A; therefore, A must be the limiting reagent. Just to check that, how much B would you need for 100% reaction. That would be
6 mols A x (1 mol B/4 mols A) = 1.5 mols B and you have that much (which just proves A is the limiting reagent). Looks to me like you started with 12 mols and ended up with 2 mols (using 10 mols).
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