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Posted by **Kristina** on Wednesday, October 8, 2008 at 12:58am.

- 3rd grade -
**Zack**, Wednesday, October 8, 2008 at 1:25am3rd graders = x

4th graders = x

5th graders = x + 6 (this is because there are 6 MORE 5th graders than 3rd grade)

Make an equation

x + x + (x + 6)= 33

group like terms

3x + 6 = 33

subtract 6 from both sides to get x alone

3x = 27

divide both sides by 3

x = 9

PLUG IN 9 for x

3rd graders = x

4th graders = x

5th graders = x + 6

add them to double check. Good luck

- 3rd grade -
**amalia**, Thursday, October 23, 2008 at 7:38pmwhat ever manger lser

- 3rd grade -
- 3rd grade -
**Alexa**, Wednesday, October 8, 2008 at 1:31amThird graders: x

Fifth graders: 6+x

Fourth graders: x (equal number as third graders)

Assuming that there is no other grades in the band

33 = x+(x+6)+x

33 equals the sum of all the parts

33 = 3x +6

Bring together like terms

27 = 3x

Solve for x

x = 9

There are nine third graders in the band

- 3rd grade -
**Kristina**, Wednesday, October 8, 2008 at 2:16amThank you!! I really appreciate your help! ( :

- 3rd grade -
**mlead**, Wednesday, April 10, 2013 at 7:39pmthere are 9 third graders

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