Posted by mike on .
What is the derivative of 4^[sin(pi*x)]? And how do you go about solving it? thanks

Calc 
Count Iblis,
4^[sin(pi*x)] =
exp[log(4) sin(pi x)]
So, by the chain rule, the derivative is:
exp[log(4) sin(pi x)] log(4) pi
cos(pi x) =
pi log(4) 4^[sin(pi x)] cos(pi x)