Posted by House on .
A football is kicked with an initial velocity of 42 ft/sec at an angle of 35 degrees with the horizontal. How far has the football traveled horizontally after 0.5 sec? round to nearest tenth.
Could someone explain this please?

Math 
House,
x=tvcos(x)
x=t(42)cos35
x=42tcos35
y=tvsin(x)1/2gt^2+h
y=t(42)sin351/2(32)t^2+0.5
y=42tsin3516t^2+0.5
0.5=42tcos35
t=0.5/42cos35
t=0.00975181
I don't know, I just followed an example in my book.